java 序列化对象如何排除指定属性呢?

java 中序列化对象有多种方式:struts2 ,jackson,json-lib

(1)使用struts2 json插件

依赖的jar包:struts2-json-plugin-2.3.15.3.jar,xwork-core-2.3.15.3.jar,当然还有servlet-api.jar

范例:

private String getMessageJson(PushMessage message) {
        List<Pattern> excludeProperties = new ArrayList<Pattern>();
        Pattern pattern1 = Pattern.compile("description");
        Pattern pattern2 = Pattern.compile("creator");// 创建者ID
        Pattern pattern3 = Pattern.compile("modifier");// 修改者ID
        Pattern pattern4 = Pattern.compile("deliverTime");//
        Pattern pattern5 = Pattern.compile("description");//
        Pattern pattern6 = Pattern.compile("createTime");//
        Pattern pattern7 = Pattern.compile("modifyTime");//

        excludeProperties.add(pattern1);
        excludeProperties.add(pattern2);
        excludeProperties.add(pattern3);
        excludeProperties.add(pattern4);
        excludeProperties.add(pattern5);
        excludeProperties.add(pattern6);
        excludeProperties.add(pattern7);

        String pushJsonStr = null;
        try {
            PushMessage pushMessage = null;
            try {

                pushMessage = message.clone();
            } catch (CloneNotSupportedException e) {
                logger.error("pushmessage clone failed.", e);
            }
            pushJsonStr = JSONUtil.serialize(pushMessage, excludeProperties,
                    null, false, false);
            logger.info("after struts serialize:" + pushJsonStr);
        } catch (JSONException e) {
            logger.error("struts serialize failed.", e);
        }// TOOD 判断json字符串的长度是否超过了256
        return pushJsonStr;
    }

 注意:Pattern.compile 的参数就是要排除的成员变量名称(即description,creator,modifier都是成员变量名称)

 

 

(2)使用Jackson

官网：

参考：

 

依赖的jar:jackson-mapper-lgpl-1.9.9.jar,jackson-core-lgpl-1.9.9.jar

如果使用maven,则在pom.xml中添加依赖

 

<!-- Json转化模块 -->
        <dependency>
            <groupId>org.codehaus.jackson</groupId>
            <artifactId>jackson-mapper-lgpl</artifactId>
            <version>1.9.9</version>
        </dependency>

 如何排除指定属性呢?

 

方式一:

先把要准备排除的属性的值设置为null

然后设置mapper的包含策略,看下面的实例:

 

public void test_jackson(){
//      Map map=new HashMap();
//      map.put("name", "黄威");
        List<Student2> stus=null;
        stus=new ArrayList<Student2>();
        Student2 stu=new Student2();
        stus.add(stu);
        stu.setAddress(null);
        ObjectMapper mapper = new ObjectMapper();
        mapper.setSerializationInclusion(Inclusion.NON_NULL);
        String content = null;
        try {
            content = mapper.writeValueAsString(stus);
            System.out.println(content);
        } catch (JsonGenerationException e) {
            e.printStackTrace();
        } catch (JsonMappingException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }

    }

 我把Student2对象的属性address设置为null,那么序列化时就会排除address属性.

 

注意:mapper.setSerializationInclusion(Inclusion.NON_NULL); 表示排除值为null的属性(成员变量)

方式二:使用FilterProvider

 

@Test
    public void test_jackson2(){
        List<Student2> stus=null;
        stus=new ArrayList<Student2>();
        Student2 stu=new Student2();
        stus.add(stu);
        stu.setClassroom("36班");
        ObjectMapper mapper = new ObjectMapper();
        String content = null;
        try {
//          content = mapper.writeValueAsString(stus);
            SimpleBeanPropertyFilter theFilter = SimpleBeanPropertyFilter.serializeAllExcept("schoolNumber");
            FilterProvider filters = new SimpleFilterProvider().addFilter("myFilter", theFilter);

            content = mapper.writer(filters).writeValueAsString(stu);
            System.out.println(content);
        } catch (JsonGenerationException e) {
            e.printStackTrace();
        } catch (JsonMappingException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }

    }

 注意:在排除属性的对象上面增加注解:@JsonFilter("myFilter")

参考:http://www.baeldung.com/jackson-ignore-properties-on-serialization